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Find the two third life t{2/3} of a 1st ...

Find the two third life `t_{2/3}` of a 1st order reaction in which `k=5.48*10^-14 sec^-1`.

A

`201 times 10^(13)s`

B

`2.01 times 10^(13)s`

C

`201 times 10^(20)s`

D

`0.201 times 10^(10)s`

Text Solution

Verified by Experts

The correct Answer is:
B
Let, initial concentration = a
`" "` Final concentration = `a-2/3a=a/3`
`" "t_(2//3)=(2.303)/klog""a/(a//3)`
`" "=(2.303)/(5.48 times 10^(-14))log3`
`" "=2.01 times 10^(13)s`
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