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5.6 g of an organic compound on buring w...

5.6 g of an organic compound on buring with excess of oxygen gave 17.6 g of `CO_(2) and 7.2 g` of `H_(2)O`. The organic compound is :

A

`C_(6)H_(6)`

B

`C_(4)H_(8)`

C

`C_(3)H_(8)`

D

`CH_(3)COOH`

Text Solution

Verified by Experts

The correct Answer is:
B
`underset(5.6g)("Organic compound") overset([O])(rarr) underset(17.6g)(CO_(2))+underset(7.2g)(H_(2)O)`
`" % of C"=12/144 times (17.6)/(5.6) times 100=85.7%`
`" % of H"=2/18 times (7.2)/(5.6) times 100=14.28%`
`{:("Element", "Percentage", "Relative no. of atoms", "Simplest ratio"), (C, 85.7, 85.7//12=7.14, 7.14//7.14=1), (H, 14.28, 14.28//1=14.28, 14.28//7.14=2):}`
Hence, empirical formula of compound = `CH_(2)`
`therefore` molecular formula of compound `=C_(4)H_(8)`
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