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Given the standard reduction potentials ...

Given the standard reduction potentials `Zn^(2+)//Zn=-0.74V, Cl_(2)//Cl^(-)=1.36V, H^(+)//1//2H_(2)=0V and Fe^(2+)//Fe^(3+)=0.77V`. The order of increasing strength as reducing agent is :

A

`Cl^(-), Zn, H_(2), Fe^(2+)`

B

`H_(2), Zn, Fe^(2+), Cl`

C

`Cl^(-)Fe^(2+), Zn, H_(2)`

D

`Cl^(-), Fe^(2+), H_(2), Zn`

Text Solution

Verified by Experts

The correct Answer is:
D
The substances which have lower reduction potentials are stronger reducing agents. Hence the order of strength of reducing agent is increases in the following order :
`" "underset("Strength of reducing agent increases")overset(Cl lt Fe^(2+) lt H_(2) lt Zn)(rarr)`
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