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The orbital angular momentum of an elect...

The orbital angular momentum of an electron revolving in a p-orbital is :

A

A) zero

B

B) `h/sqrt(2pi)`

C

C) `h/(2pi)`

D

D)`1/2""h/(2pi)`

Text Solution

Verified by Experts

The correct Answer is:
B
Orbital angular momentum `=sqrt(l(l+1))h/(2pi)`
For p-orbital, `" "l=1`
`therefore" "` orbital angular momentum
`" "=sqrt(1(1+1))h/(2pi)=(sqrt(2)h)/(2pi)=h/(sqrt(2)pi)`
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