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Calculate the equilibrium constant for t...

Calculate the equilibrium constant for the reaction, at `25^(@)C`
`Cu(s)+2Ag^(+)(aq) rarr Cu^(2+)(aq)+2Ag(s)`
at `25^(@)C, E^(@)""_("cell")=0.47V, R=8.314JK^(-1), F=96500C:`

A

`1.8 times 10^(15)`

B

`8.5 times 10^(15)`

C

`1.8 times 10^(10)`

D

`85 times 10^(15)`

Text Solution

Verified by Experts

The correct Answer is:
B
`E_("cell")^(@)=(0.059)/2logK_(c)`
`" "logK_(c)=(E^(@)""_(cell) times 2)/(0.059)`
`" "logK_(c)=(0.47 times 2)/(0.059)`
`" "K_(c)=8.5 times 10^(15)`
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