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One Faraday of electricity is passed thr...

One Faraday of electricity is passed through molten `Al_(2)O_(3)`, aqueous solution of `CuSO_(4)` and molten NaCl taken in three different electrolytic cells connected in series. The mole ratio of Al, Cu and Na deposited at the respective cathode is

A

`2:3:6`

B

`6:2:3`

C

`6:3:2`

D

`1:2:3`

Text Solution

Verified by Experts

The correct Answer is:
A
`{:(Al^(3+), +, 3e^(-), rarr, Al),(,,3F,,"1 mol"),(,,1F,,"1/3 mol"),(Cu^(2+),+,2e^(-),rarr,Cu),(,,2F,,"1mol"),(,,1F,,"1/2 mol"),(Na^(+),+,e^(-),rarr,Na),(,,1F,,"1 mol"):}`
`therefore` The mole ratio of Al, Cu and Na deposited at the respective cathode is
`(1)/(3) : (1)/(2) : 1` or `2:3:6`
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