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If the activation energy for the forward...

If the activation energy for the forward reaction is `150 k J mol^(-1)` and that of the reverse reaction is `260 kJ mol^(-1)`, what is the enthalpy change for the reaction ?

A

`410 kJ mol^(-1)`

B

`110 kJ mol^(-1)`

C

`-110 kJ mol^(-1)`

D

`-410 kJ mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
C
Enthalpy change for a reversible reaction.
`Delta H = E_(a)` (forward) - `E_(a)` (backward)
`Delta H = 150 - 260 = -110 kJ mol^(-1)`
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