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The threshold frequency of a metal corre...

The threshold frequency of a metal corresponds to the wavelength of x nm. In two separate experiments A and B, incident radiations of wavelengths 1/2x nm and 1/4x nm respectively are used. The ration of kinetic energy of the released electrons in experiment 'B' to that in experiment 'A' is

A

`1//3`

B

2

C

4

D

3

Text Solution

Verified by Experts

The correct Answer is:
A
In experiment A, incident radiations of wavelength used `=1/(2)x`
In experiment B, incident radiations of wavelength used `=1/(4)x`
The ration of kinetic energy of the released electrons in experiment .B. to that in experiment .A.:
`(KE)_(B)/((KE)_(A))=(1/(lamda_(B))-1/(lamda_(0)))/(1/(lamda_(A))-1/(lamda_(0)))` [`letslamda_(0)=x`]
`(KE)_(B)/((KE)_(A))=(x-x)/(2/(x)-1/(x))=3`
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