Which of the following changes in the respective bond order values are caused by removal of an electron from `N_(2)andF_(2)` molecules?

Options

A. Decrease by 0.5 in both
B. Increase by 0.5 in both
C. Increase by 0.5 in the former and decreases by 0.5 in ther latter
D. Decrease by 0.5 in the former and increase by 0.5 in the latter

Answer

C

Explanation

`N_(2)` (total electrons = 14)
`sigma1s^(2),sigma1s^(2),sigma2s^(2),sigma2s^(2),pi2p_(x)^(2)=pi2p_(y)^(2),sigma2p_(z)^(2)`
`F_(2)` (total electrons = 18)
`sigma1s^(2),sigma1s^(2),sigma2s^(2),sigma2s^(2),sigma2p_(z)^(2),pi2p_(x)^(2)=pi2p_(y)^(2),pi2p_(x)^(2)=pi2p_(y)^(2)`
For `N_(2)` the valence orbital is bonding molecular orbital and for `F_(2)`, it is antibonding molecular orbital.
So, bond order decrease by 0.5 in the former and increase by 0.5 in the water.