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A binary solid (A^(+)B^(-)) has a zinc b...

A binary solid `(A^(+)B^(-))` has a zinc blende structure with `B^(-)` ions constituting the lattice and `A^(+)` ions occupying 25% tetrahedral holes. The formula of solid is:

A

`A_(2)B`

B

`AB_(3)`

C

`AB_(2)`

D

`A_(2)B_(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Let number of octahedral holes in the lattice = x
`therefore` Number of tetrahedral holes in the lattice = 2x
(`because` Number of tetrahedralholes = 2x number of octahedral holes)
Now, `A^(+)` ions occupy 25% of tetrahedral holes. Hence, number of tetrahedral holes occupied in the lattice = `2x xx25%=2x xx25/(100)=x/(2)`
Since, number of octahedral holes = Number of lattice points.
`therefore` Number of octahedral holes = x
`therefore` Molecular formula of the crystal is
`A_(x//2)B_(x)orAB_(2)`
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