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The enthalpy change for a reaction at eq...

The enthalpy change for a reaction at equilibrim is `-20.5kJ"mol"^(-1)`. Then the entropy change for this equilibrim at 410 K is

A

`+50JK^(-1)"mol"^(-1)`

B

`+55JK^(-1)"mol"^(-1)`

C

`+75JK^(-1)"mol"^(-1)`

D

`-50JK^(-1)"mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
Given, the enthalpy change
`=-20.5kJ//mol`
`=-20.5xx10^(3)J//mol`
Temperature (T) = 410 K
Entrophy change
`DeltaS=(DeltaH)/(T)=((-20.5xx10^(3)))/(410)`
`=-50JK^(-1)"mol"^(-1)`
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