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How many moles of platinum will be depos...

How many moles of platinum will be deposited on the cathode when 0.60 F of electricity is passed through a 1.0 M solution of `Pt^(4+)`?

A

`0.60 "mol"`

B

`0.15 "mol"`

C

`0.30"mol"`

D

`0.45"mol"`

Text Solution

Verified by Experts

The correct Answer is:
A
`Pt^(4+)+4e^(-)rarrPt`
When 4F electricity passed then gives = 1 moles Pt
Let when 0.60F electricity passed through solution then number of moles of Pt = x
So, number of moles
`(x)=(0.60F)/(4F)=0.15"moles"`
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