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The rate constant of the reaction, 2N(2)...

The rate constant of the reaction, `2N_(2)O_(5) rarr 4NO_(2) + O_(2)` at 300 K is `3 xx 10^(-5)S^(-1)`. If the rate of the reaction at the same tamperature is `2.4 xx 10^(-5) mol dm^(-3) s^(-1)`, then the molar concentration of `N_(2)O_(5)` is

A

0.4 M

B

0.8 M

C

0.04 M

D

0.08 M

Text Solution

Verified by Experts

The correct Answer is:
B
Given,
k (rate constant) `= 3 xx 10^(-5) s^(-1)` which indicates that reaction is of first order. (`because` unit is `s^(-1)`)
`therefore` r (rate of reaction) `= k ["concentration"]^(1)`
[concentration] `= (2.4 xx 10^(-5))/(3.0 xx 10^(-5)) = 0.8 M`
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