Critical density of a gas having molecular weight `39 g mol^(-1)` is `0.1 xx 10^(3) gcm^(-3)`. Its critical volume in L `mol^(-1)` is

Options

A. 0.39
B. 3.9
C. 0.039
D. `39.0`

Answer

A

Explanation

Given,
Critical density `= 0.1 xx 10^(3) g cm^(-3)`
Critical mass = molecular weight = 39 g
`because` Critical density `= ("Critical mass")/("Critical volume")`
`therefore` Critical volume (in L `mol^(-1)`)
`= ("Critical mass")/("Critical density") = (39)/(0.1 xx 10^(3))`
`= 0.390 L mol^(-1)`