The hybridised state of `Al^(3+)` in the complex ion formed when `AlCl_(3)` is treated with aqueous acid is

Options

A. `sp^(3)`
B. `dsp^(2)`
C. `sp^(3)d^(2)`
D. `sp^(2)d`

Answer

C

Explanation

`AlCl_(3) +` aqueous acid `rarr [Al(H_(2)O)_(6)]^(3+)`.
`Al^(3+)` ions give a complex ion in which `Al^(3+)` ion form six coordinate covalent bonds with six `H_(2)O` molecules. Hence, it shows `sp^(3)d^(2)` hybridisation.
(Due to availability of vacant 3d-orbitals.)
`Al = 3s^(2)3p^(1)`
`Al^(3T) = 3s^(0)`

Four electrons pairs denoted by `6 H_(2)O` molecules.