Which of the following pair have identical bond order?

Options

A. `CN^(-)` and `NO^(+)`
B. `CN^(-)` and `O_(2)^(-)`
C. `CN^(-)` and `CN^(+)`
D. `NO^(+)` and `O_(2)^(-)`

Answer

A

Explanation

For paris having identical bond order have identical number of electrons
number of electrons for `NO^(+)` =6+7+1=14
Number of electron for `O_(2)^(-)=8+8+1=17`
Hence `CN^(-)` and `NO^(+)` have same bond order