Home
Class 12
CHEMISTRY
For the process A (l, 0.05 "atm", 32^(@...

For the process A `(l, 0.05 "atm", 32^(@) C) rarr` A (g, 0.05 atm, `32^(@)` C) The correct set of thermodynamic parameters is

A

`triangle G=0` and `triangles=-ve`

B

`triangle G=0` and `triangleS=+Ve`

C

`triangle G=+` ve and `triangle S=0`

D

`triangle` G =- ve and `triangle` S=0

Text Solution

Verified by Experts

The correct Answer is:
B

(i) `because`n and T are constant
`therefore triangle g=0 i.e`
System is equilibrium
(ii) `because P rarr` decreases
`therefore` correct answer is `rarr` (B)
Promotional Banner

Similar Questions

Explore conceptually related problems

The reaction A(g)+2B(g) rarrC(g)+D(g) is an elementary process In an experiment the initial partial pressure of A and B are p_(A) =0.60 and p_(B) =0.80 atm when p_(c )=0.2 atm the rate of the reaction relative to the initial rate is

The density of a gas was found to be 2.92gl^-1 at 27^@C and 2.0 atm. Calculate the molar mass of the gas.

An amount of 3 mole H_(2) O(l) at 100^(@)C and 1 atm is converted into H_(2) O (g) at 100^(@)C and 5 atm. DeltaG for the process is

Plot of log x/m against log p is a straight line inclined at an angle of 45^(@) . When the pressure is 0.5 atm and Freundlich parameter , k is 10 , the adsorbent will be (log 5=06990)

In a reaction 2A + B to 3C , the concentration of A decreases from 0.5 mol L^(-11) to 0.3 mol L^(-1) in 10 minutes. The rate of production of 'C during this period is: