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y = log (a) x + log (x) a + log (x) x + ...

`y = log _(a) x + log _(x) a + log _(x) x + log _(a) a, ` then `(dy)/(dx)` is equal to :

A

`1/x + x log a `

B

`(log a )/(x) + (x)/( log a)`

C

`(1)/( x log a ) + x log a `

D

`(1)/( x log a) - (log a )/(x ( log x ) ^(2))`

Text Solution

Verified by Experts

The correct Answer is:
D
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