The real part of [1 + cos ((pi )/(5)) + ...

The real part of `[1 + cos ((pi )/(5)) + i sin ((pi)/(5)) ]^(-1)` is :

A

1

B

`1/2`

C

`1/2 cos ((pi)/(10))`

D

`1/2 cos ((pi)/(5))`

Verified by Experts

The correct Answer is:

B

Similar Questions

Explore conceptually related problems

If z= cos (pi)/(3) - i sin (pi)/(3) then z^(2)-z+1 is equal to

cos^(4) ""(pi)/(12) - sin^(4)"" (pi)/(12) is equal to

cos ^(-1) [ cos ((7pi)/(5))] is equal to

If z _(r) = cos ((pi)/(2 ^(r))) + i sin ((pi )/( 2 ^(r))), then z _(1) . z _(2). z _(3)... upto oo equals : a)-3 b)-2 c)-1 d)0

One of the value of ("cos"(pi)/(6) +i "sin"(pi)/(6))^((1)/(2)) + ("cos"(pi)/(6)- i "sin"(pi)/(6))^((11)/(2)) is

The complex number sqrt2 [ sin "" (pi)/(8) + i cos ""(pi)/(8) ] ^(6) represents

tan [ 3 tan^(-1) ((1)/(5)) - (pi)/(4) ] is equal to

((1+cos(pi/(12))+i sin ((pi)/(12)))/(1+cos (pi/(12))- i sin (pi/(12))))^(72) is equal to

The principal argument of the complex number z = (1+ sin""(pi)/(3) + icos""(pi)/(3))/(1+sin""(pi)/(3) - i cos ""(pi)/(3)) is

The value of sin^(2)""(pi)/(8) + sin^(2)""(3pi)/(8) + sin^(2)""(5pi)/(8) + sin^(2) ""(7pi)/(8) is equal to a) (1)/(8) b) (1)/(4) c) (1)/(2) d)2