Home
Class 12
MATHS
The length of the longest size rectangel...

The length of the longest size rectangel of maximum area that can be inscribed in a semicircle of radius 1, so that 2 vertices lie on the diameter, is
a)`sqrt2` b)2 c)`sqrt3` d)`(sqrt2)/(3)`

A

`sqrt2`

B

2

C

`sqrt3`

D

`(sqrt2)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius is (2R)/sqrt3 . Also find the maximum volume.

(sqrt3+sqrt2)^(4)- (sqrt3-sqrt2)^(4) =

Prove (2+sqrt3)(2-sqrt3)=1

(sqrt3+sqrt2)(sqrt3-sqrt2) എത്ര?

sin 765^(@) is equal to a)1 b)0 c) sqrt(3)//2 d) 1//sqrt2

The minimum values of sin x + cos x is a) sqrt2 b) -sqrt2 c) (1)/(sqrt2) d) - (1)/(sqrt2)

The value of "tan"15^(@)+"tan"75^(@) is a) 2sqrt(3) b)2 c) 2-sqrt(3) d)4

If the point (a,b) on the curve y= sqrt(x) is close to the point (1,0) , then the value of ab is a) 1/2 b) (sqrt2)/(2) c) 1/4 d) (sqrt2)/(4)

If in a triangle ABC, a = 15, b = 36, c =39, then sin""C/2 is equal to :a) sqrt(3)/2 b) 1/2 c) 1/sqrt(2) d) -1/sqrt(2)

An equilateral triangle is inscribed in the parabola y^(2) = 4x . If a vertex of the triangle is at the vertex of the parabola, then the length of side of the triangle is a) sqrt(3) b) 8 sqrt(3) c) 4 sqrt(3) d) 3 sqrt(3)