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If int(0)^(pi//2)sin^(6)xdx=(5pi)/(32), ...

If `int_(0)^(pi//2)sin^(6)xdx=(5pi)/(32)`, then the value of `int_(-pi)^(pi)(sin^(6)x+cos^(6)x)dx` is --

A

`5pi//8`

B

`5pi//16`

C

`5pi//2`

D

`5pi//4`

Text Solution

Verified by Experts

The correct Answer is:
D
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