Home
Class 12
MATHS
Gas is being pumped into a spherical ba...

Gas is being pumped into a spherical balloon the rate of `30ft^(3)//min` . Then the rate at which the radius increases when it reaches the value 15 ft is a)`(1)/(15pi)ftmin` b)`(1)/(30pi)ft//min` c)`(1)/(20)ft//min` d)`(1)/(25)ft//min`

A

`(1)/(15pi)ftmin`

B

`(1)/(30pi)ft//min`

C

`(1)/(20)ft//min`

D

`(1)/(25)ft//min`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A spherical iron ball of radius 10 cm , coated with a layer of ice of uniform thickness , melts at a rate of 100picm^(3)//min . The rate at which the thickness decreases when the thickness of ice is 5 cm , is a)1 cm/min b)2 cm/min c) (1)/(376) cm/min d)5 cm/min

The value of "sin"(31)/(3)pi is a) (sqrt3)/(2) b) (1)/(sqrt2) c) (-sqrt3)/(2) d) (-1)/(sqrt2)

The point on the curve y=5 + x-x^(2) at which the normal makes equal intercepts is a) (1,5) b) (0,-1) c) (-1,3) d) (0,5)

The radius of a cylinder is increasing at the rate of 5 cm/min so that its volume is constant. When its radius is 5 cm and height is 3 cm, then the rate of decreasing of its height is a)6 cm/min b)3 cm/min c)2cm/min d)5 cm/min

Water is running into a conical vessel, 15cm deep and 5cm in radius, at the rate of 0.1 cm^3//sec . When the water is 6cm deep, find at what rate is The water level rising.

A first order reaction with respect to reactant A has a rate constant 6.5 min^(-1) . If we start with 2.0 mol L^(-1) of A when would A reach the value 0.5 mol L^(-1)

The radius of a circle is increasing at the rate of 0.1 cm/s. When the radius of the circle is 5 cm, the rate of change of its area, is :a) -pi" "cm^(2)//s b) 10pi" "cm^(2)//s c) 0.1pi" "cm^(2)//s d) pi" "cm^(2)//s

Water is running into a conical vessel, 15cm deep and 5cm in radius, at the rate of 0.1 cm^3//sec . When the water is 6cm deep, find at what rate is The wetted surface of the vessel increasing.

The value of sin^(-1){cos(4095^(@))} is equal to a) -(pi)/(3) b) (pi)/(6) c) -(pi)/(4) d) (pi)/(4)

If tan^(-1)2x+tan^(-1)3x=(pi)/(2) , then the value of x is equal to a) (1)/(sqrt(6)) b) (1)/(6) c) (1)/(sqrt(3)) d) (1)/(sqrt(2))