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In triangle ABC, the value of (cot""A/2c...

In triangle ABC, the value of `(cot""A/2cot ""B/2-1)/(cot ""A/2 cot ""B/2)` is

A

`a/(a+b+c)`

B

`c/(a+b+c)`

C

`(2a)/(a+b+c)`

D

`(2c)/(a+b+c)`

Text Solution

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The correct Answer is:
D
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