If x^2+y^2=t -1/t and x^4+y^4=t^2+1/t^2 ...

If `x^2+y^2=t -1/t and x^4+y^4=t^2+1/t^2` then `(dy)/ (dx)` is equal to a)`1/(x^2y^3)` b)`1/(xy^3)` c)`1/(x^2y^2)` d)`1/(x^3y)`

A

`1/(x^2y^3)`

B

`1/(xy^3)`

C

`1/(x^2y^2)`

D

`1/(x^3y)`

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The correct Answer is:

D

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