Let f(x)=(x-7)^2 (x-2)^7, x in [2,7] the...

Let `f(x)=(x-7)^2 (x-2)^7, x in [2,7]` the value of
`theta in (2,7)` such that `f'(theta)=0` is equal to

A

`49/4`

B

`53/9`

C

`53/7`

D

`49/9`

Verified by Experts

The correct Answer is:

B

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