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If a(1), a(2), a(3),….,a(n) are in AP an...

If `a_(1), a_(2), a_(3),….,a_(n)` are in AP and `a_(1) = 0`, then the value of `((a_(3))/(a_(2)) + (a_(4))/(a_(3)) +...+(a_(n))/a_(n-1))-a_(2) ((1)/(a_(2)) + (1)/(a_(3))+...+(1)/(a_(n-2)))` is equal to a)`(n-2) + (1)/((n-2))` b)`(1)/((n-2))` c)(n - 2) d)(n - 1)

A

`(n-2) + (1)/((n-2))`

B

`(1)/((n-2))`

C

(n - 2)

D

(n - 1)

Text Solution

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The correct Answer is:
A
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