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If (b + c) (y + z) - ax = b - c, (c + a...

If `(b + c) (y + z) - ax = b - c,
(c + a) (z + x) - by = c - a and
(a + b) (x + y) - cz = a - b`, where a + b + c `ne` 0, then x is equal to a)`(c + b)/(a + b + c)` b)`(c - b)/(a + b + c)` c)`(a - b)/(a + b + c)` d)`(a + b)/(a + b + c)`

A

`(c + b)/(a + b + c)`

B

`(c - b)/(a + b + c)`

C

`(a - b)/(a + b + c)`

D

`(a + b)/(a + b + c)`

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The correct Answer is:
B
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