Home
Class 12
MATHS
The position vector of the centroid of t...

The position vector of the centroid of the `Delta` ABC is `2i + 4j + 2k`. If the position vector of the vertex A is 2i + 6j + 4k, then the position vector of midpoint of BC is a)2i + 3j + k b)2i + 3j - k c)2i - 3j - k d)`-2i - 3j - k`

A

2i + 3j + k

B

2i + 3j - k

C

2i - 3j - k

D

`-2i - 3j - k`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Write the unit vector in direction of i+2j-3k .

Find the direction cosine of the vector 2i+2j-k.

The triangle formed by the three points whose position vectors are 2i + 4j -k , 4i +5j + k and 3i + 6j - 3k , is

If the vector equation of a line is barr=i+j+k+mu(2i-3j-4k) , then the Cartesian equation of the line is

Find the projection of a vector i+3j+7k on the vector 7i-j+8k .

Given the position vectors of three points as A(i-j+k),B(4i+5j+7k)C(3i+3j+5k) Find vec(AB) and vec(BC) .

The projection of the vector 2i + aj - k on the vector i - 2j + k is (-5)/(sqrt(6)) . Then, the value of a is equal to

The position vectors of three points A,B,C are given to be i+3j+3k , 4i+4k , -2i+4j+2k respectively.Find vec(AB) and vec(AC)

Consider the vectors veca=2i+j+3k,vecb=i+4j-k .Find the projection of veca on vecb .

The position vectors of the points A and B with respect to O are 2i+2j+k and 2i+4j+4k . The length of the internal bisector of angleBOA of DeltaAOB is a) sqrt(136)/(9) b) sqrt(136)/(3) c) (20)/(3) d) sqrt(217)/(9)