If f(x)=|(x,lambda),(2lambda,x)|, then f...

If `f(x)=|(x,lambda),(2lambda,x)|`, then `f(lambdax)-f(x)` is equal to

A

`x(lambda^(2)-1)`

B

`2lambda(x^(2)-1)`

C

`lambda^(2)(x^(2)-1)`

D

`x^(2)(lambda^(2)-1)`

Verified by Experts

The correct Answer is:

D

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