Home
Class 12
MATHS
The vector equation of the plane through...

The vector equation of the plane through the point `(2,1,-1)` and parallel to the plane `r.(i+3j-k)=0` is a)`r.(i+9j+11k)=6` b)`r.(i-9j+11k)=4` c)`r.(i+3j-k)=6` d)`r.(i+3j-k)=4`

A

`r.(i+9i+11k)=6`

B

`r.(i-9j+11k)=4`

C

`r.(i+3j-k)=6`

D

`r.(i+3j-k)=4`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Similar Questions

Explore conceptually related problems

Find the distance of the point (2,3,4) from the plane barr.(3i-6j+2k)=-11 .

Find the distance of the point (-1,-2,3) from the Plane barr.(2i-3j+4k)=4

Find the vector equation of the Plane Passing through the intersection of the planes barr.(i+j+k)=6 and barr.(2i+3j+4k)=-5 and through the point (1,1,1).

Show that the line barr=i+j+lambda(2i+j+4k) is parallel to the plane barr.(-2i+k)=5 .

If the Cartesian equation of a plane is x+y+z=12 , then the vector equation of the plane is.... a) barr.(2i+j+k)=12 b) barr.(i+j+k)=12 c) barr.(i+j+2k)=12 d) barr.(i+3j+k)=12

The distance between the planes r. (i+ 2j - 2k ) + 5 =0 and r. (2i + 4j - 4k ) - 16 =0 is

Consider a plane passing through the point (5,2,-4) and perpendicular to the line barr=(i+j)+lambda(2i+3j-k) Find its distance from the point (1,2,-1).

Find the distance between the line barr=i+j+lambda(2i+j+4k) and the plane barr.(-2i+k)=5 .

Consider a plane passing through the point (5,2,-4) and perpendicular to the line barr=(i+j)+lambda(2i+3j-k) Write the equation in Cartesian form.

A vector of magnitude 7 units, parallel to the resultant of the vectors a=2i-3j-2k and b=-i+2j+k , is