If Sigma(k=1)^(n)k(k+1)(k-1)=pn^(4)+qn^(...

If `Sigma_(k=1)^(n)k(k+1)(k-1)=pn^(4)+qn^(3)+tn^(2)+sn`, where p, q, t and s are constants, then the value of s is equal to

A

`-(1)/(4)`

B

`-(1)/(2)`

C

`(1)/(2)`

D

`(1)/(4)`

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The correct Answer is:

B

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