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If a, b, c and d are in GP, then (a+b+c+...

If a, b, c and d are in GP, then `(a+b+c+d)^(2)` is equal to

A

`(a+b)^(2)+(c+d)^(2)+2(b+c)^(2)`

B

`(a+b)^(2)+(c+d)^(2)+2(a+c)^(2)`

C

`(a+b)^(2)+(c+d)^(2)+2(b+d)^(2)`

D

`(a+b)^(2)+(c+d)^(2)+(b+c)^(2)`

Text Solution

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The correct Answer is:
A
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