If t5 , t10 and t25 are 5th, 10th and 25...

If `t_5 , t_10 and t_25` are 5th, 10th and 25th terms of an AP respectively, then the value of `abs{:(t_5 , t_10 , t_25),(5, 10 , 25),(1, 1, 1 ):}` is

A

`-40`

B

`1`

C

`-1`

D

`0`

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The correct Answer is:

D

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