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If `a _(1) , a _(2), a _(3),...` are in AP, then the value of `|{:(a _(1), a _(2) , 1), ( a _(2), a _(3),1), (a _(3), a _(4), 1):}|` is equal to

A

`a _(4) - a _(1)`

B

`(a _(1) + a _(4))/( 2)`

C

`a _(4) - a _(1)`

D

`(a _(2) + a _(3))/( 2)`

Text Solution

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The correct Answer is:
D
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