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A circle of radius sqrt8 is passing thro...

A circle of radius `sqrt8` is passing through origin and the point (4,0). If the centre lies on the line y =x, then the equation of the circle is a)`(x -2) ^(2) + (y-2) ^(2) = 8` b)`(x + 2) ^(2) + (y +2) ^(2) =8` c)`(x -3) ^(2) + (y -3) ^(2) = 8` d)`(x -4) ^(2) + (y-4) ^(2) = 8`

A

`(x -2) ^(2) + (y-2) ^(2) = 8`

B

`(x + 2) ^(2) + (y +2) ^(2) =8`

C

`(x -3) ^(2) + (y -3) ^(2) = 8`

D

`(x -4) ^(2) + (y-4) ^(2) = 8`

Text Solution

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The correct Answer is:
A
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