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The foci of the ellipse (x^(2))/(16) + ...

The foci of the ellipse ` (x^(2))/(16) + (y^(2))/(b^(2))=1 ` and the hyperbola ` (x^(2))/(144) - (y^(2))/(81) =(1)/(25)` coincide. Then the value of ` b^(2)` is :
a)1 b)5 c)7 d)9

A

1

B

5

C

7

D

9

Text Solution

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The correct Answer is:
C
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