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If log(0.3) (x-1) lt log (0.09) (x-1) ...

If `log_(0.3) (x-1) lt log _(0.09) (x-1) , " then " x ne 1 ` lies in : a)(1,2) b)(0,1) c)`(1,infty)` d)` (2,infty)`

A

(1,2)

B

(0,1)

C

`(1,infty)`

D

` (2,infty)`

Text Solution

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The correct Answer is:
D
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