Home
Class 12
MATHS
The statement "~"(p rarrq) is equivalent...

The statement `"~"(p rarrq)` is equivalent to :
a)`p wedge(~q)` b)`~p wedgeq` c)`p wedge q`d)`~ p wedge ~q`

A

`p wedge(~q)`

B

`~p wedgeq`

C

`p wedge q`

D

`~ p wedge ~q`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

(p wedge ~q) wedge (~p wedge q) is

~[p vee (-q)] is equal to

If p: It is snowing, q:I am cold, then the compound statement "It is snowing and it is not that I am cold" is given by a) pwedge(~q) b) pwedgeq c) (~p)wedgeq d) (~p)wedge(~q)

The converse of the statement p rArr q is

~[(~p) ^^q] is logically equivalent to a) ~ (p vv q) b) ~ [p ^^ (~q)] c) p ^^ (~q) d) p vv (~q)

(b)~[(~p)^q] is logically equivalent to

Let p, q, r be three simple statements. Then, ~(p vv q) vv ~ (p vv r) is equal to a) (~p) ^^ (~q vv ~ r) b) (~p) ^^ (q ^^ r) c) p ^^ (q vv r) d) p vv (q ^^ r)

Let p, q, r be three statements. Then, ~(pvv(q^^r)) is equal to a) (~p^^~q)^^(-p^^r) b) (~pvv~q)^^(~pvv~r) c) (~p^^~q)vv(~p^^~r) d) (~pvv~q)vv(~p^^~r)

Identify the false statement a) ~[p vee (~ q)]-=(~p)wedge q b) [ p vee q)] vee (~p) is a tautology c) [p vee q)] vee (~p) is a contradiction d) ~ [pwedge (~p)] is a tautology