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int (x^(2) +1)sqrt(x+1)dx is equal to ...

`int (x^(2) +1)sqrt(x+1)dx` is equal to
a)`((x+1)^(7//2))/(7) - 2((x+1)^(5//2))/(5) + 2((x+1)^(3//2))/(3)+c`
b)`2[((x+1)^(7//2))/(7) - 2((x+1)^(5//2))/(5) + 2((x+1)^(3//2))/(3)]+c`
c)`((x+1)^(7//2))/(7) - 2((x+1)^(5//2))/(5) + c`
d)`((x+ 7)^(7//2))/(7) - 3((x+1)^(5//2))/(5) + 11(x+1)^(1//2)+c`

A

`((x+1)^(7//2))/(7) - 2((x+1)^(5//2))/(5) + 2((x+1)^(3//2))/(3)+c`

B

`2[((x+1)^(7//2))/(7) - 2((x+1)^(5//2))/(5) + 2((x+1)^(3//2))/(3)]+c`

C

`((x+1)^(7//2))/(7) - 2((x+1)^(5//2))/(5) + c`

D

`((x+ 7)^(7//2))/(7) - 3((x+1)^(5//2))/(5) + 11(x+1)^(1//2)+c`

Text Solution

Verified by Experts

The correct Answer is:
B
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