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If "sin"(theta+phi)=n"sin"(theta-phi),n ...

If `"sin"(theta+phi)=n"sin"(theta-phi),n ne1`, then the value of `("tan"theta)/("tan"phi)` is a)`n/(n-1)` b)`(n+1)/(n-1)`c)`n/(1-n)`d)`(n-1)/(n+1)`

A

`n/(n-1)`

B

`(n+1)/(n-1)`

C

`n/(1-n)`

D

`(n-1)/(n+1)`

Text Solution

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The correct Answer is:
A
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