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Let the position vectors of the points A...

Let the position vectors of the points A, B and C be a, b and c, respectively. Let Q be the point of intersection of the medians of the `DeltaABC`. Then, QA + QB + QC is equal to

A

0

B

`2a+b+c`

C

`a+b+c`

D

`(a+b+c)/(3)`

Text Solution

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The correct Answer is:
A
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