Home
Class 12
MATHS
The equation of the tangent to the curve...

The equation of the tangent to the curve `y = x^(3) - 6x + 5`
at (2, 1) is

A

`6x - y - 11 = 0`

B

`6x y - 13 = 0`

C

`6x + y + 11 = 0`

D

`6x - y + 11 = 0`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

The equation of the tangent to the curve x = (t - 1)/(t + 1), y = (t + 1)/(t - 1) at t = 2 is a) x + 9y - 6 = 0 b) 9x - y - 6 = 0 c) 9x + y + 6 = 0 d) 9x + y - 6 = 0

Find the equation to the tangent to the curve y=x^2-2x+7 at (2,7)

The equation of the tangent to the curve given by x ^(2) + 2x - 3y + 3 =0 at the point (1,2) is

The equation of the tangent to the curve x^2-2xy+y^2+2x+y-6=0 at (2,2) is a) 2x+y-6=0 b) 2y+x-6=0 c) x+3y-8=0 d) 3x+y-8=0

The equation of the tangent to the curve y = x + (4)/(x ^(2)) that is parallel to the x-axis is

Find the equation of the tangent to the curve y=3x^2 at (1,1)

The slope of the tangent to he curve y=3x^(2)-5x+6 at (1, 4) is

The slope of the tangent to the curve y=x^3-1 at x=2 is………

The equation of the tangents to the circle x ^(2) + y ^(2) - 6x + 4y - 12 =0 which are parallel to the line 4x + 3y + 5=0 are :