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If A=[(1,0),(1,1)] then A^(n)+nI is e...

If A=`[(1,0),(1,1)]` then `A^(n)+nI` is equal to
a) I b)nA c)nA-I d)I+nA

A

l

B

nA

C

nA-l

D

l-nA

Text Solution

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The correct Answer is:
C
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