Acceleration due to gravity is g on the surface of the earth. Then the value of the acceleration due to gravity at a height of 32 km above earth's surface is : (Assume radius of earth to be 6400 km)

Options

A. 0.99 g
B. 0.88 g
C. 1.01 g
D. 0.9 g

Answer

A

Explanation

`g . = (g)/((1 + (h)/( R _(2)) ) ^(2)) = ( g)/(1 + (( 32)/( 6400))^(2) ) = 0.99 g `