Compressibility of water is `5xx10^(-10) m^(2)`/N. The change in volume of 100 ml water subjected to `15 xx10 ^(6)`Pa pressure will :

Options

A. no change
B. decrease by 0.75 ml
C. decrease by 1,50 mL
D. increase by 1.50 ml

Answer

D

Explanation

`K = 1/ B = ( Delta V )/( V Delta P )`
`therefore 5 xx 10 ^(-10) = ( Delta V)/( 100 xx 10 ^(-3) xx 15 xx 10 ^(6))`
`implies Delta V = 5 xx 10 ^(10) xx 100 xx 10 ^(-3) xx 15 xx 10 ^(6)`
`= 0.75 mL`
Since, pressure increases, so volume will decrease.