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The KE and PE of a particle executing SH...

The KE and PE of a particle executing SHM of amplitude a will be equal when displacement is:

A

`(a)/(2)`

B

`a sqrt2`

C

`2a `

D

`(a sqrt2)/(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
`KE = PE`
`implies 1/2 m omega ^(2) ( a ^(2) - y ^(2)) = 1/2 m omega ^(2) y ^(2)`
`implies y = (a)/( sqrt2)`
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