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A ray of light passes through an equilat...

A ray of light passes through an equilateral prism such that an angle of incidence is equal to the angle of emergence and the latter is equal to `(3)/(4)` th the angle of prism. The angle of deviation is :

A

`45 ^(@)`

B

`39^(@)`

C

`20^(@)`

D

`30^(@)`

Text Solution

Verified by Experts

The correct Answer is:
D

Angle of incidence = angle of emergence,
`i.e.i=I.`
Also, `i=(3)/(4) xx ` angle of equilateral prism
`= 3/4 xx 60^(@) = 45 ^(@)`
Thus, angle of deviation
`= i+I.-A`
`= ( 45 ^(@) + 45 ^(@) - 60^(@)) = 30^(@)`
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