If `R_(1)andR_(2)` be the resistances of the filaments of 200 W and 100 W electric bulbs operating at 220 V, then `((R_(1))/(R_(2)))` is

Options

A. 1
B. 2
C. 0.5
D. 4

Answer

C

Explanation

Power of bulb, `P=(V^(2))/(R )`
`therefore (P_(2))/(P_(1))=(R_(1))/(R_(2))`
or `(R_(1))/(R_(2))=(100)/(200)=0.5`