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Two beams of light of intensity I(1)andI...

Two beams of light of intensity `I_(1)andI_(2)` interfere to give an interference pattern. If the ratio of maximum intensity to that of minimum intensity is `(25)/(9)`, then `(I_(1))/(I_(2))` is

A

`(5)/(3)`

B

4

C

`(81)/(625)`

D

16

Text Solution

Verified by Experts

The correct Answer is:
D

`(I_(max))/(I_(min))=(25)/(9)`
or `((a_(1)+a_(2))/(a_(1)-a_(2)))^(2)=(25)/(9)`
where a denotes amplitude.
or `(a_(1)+a_(2))/(a_(1)-a_(2))=(5)/(3)`
or `(a_(1))/(a_(2))=4`
As, `("amplitude")^(2)prop` intensity
Hence, `(I_(1))/(I_(2))=((a_(1))/(a_(2)))^(2)=16`
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