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Consider the nuclear reaction X^(200)rar...

Consider the nuclear reaction `X^(200)rarrA^(110)+B^(80)`. If the binding energy per nucleon for X, A and B are 7.4 MeV, 8.2 MeV and 8.1 MeV respectively, then the energy released in the reaction is

A

70 MeV

B

200 MeV

C

190 MeV

D

10 MeV

Text Solution

Verified by Experts

The correct Answer is:
A
For X, energy `=200xx7.4=1480MeV`
For A, energy `110xx8.2=902MeV`
For B, energy `=80xx8.1=648MeV`
Therefore, energy released
`=(902+648)-1480`
`=1550-1480`
`=70MeV`
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